C++ quiz. What will be the output of the following code? <pr

What will be the output of the following code?

struct A
{
    ~A() { std::cout << "~A()"; }
};

struct B : A
{
    ~B() { std::cout << "~B()"; }
};

struct C : B
{
    ~C() { std::cout << "~C()"; }
};

int main()
{
    std::shared_ptr<A> p(false ? new B() : new C());
    return 0;
}

~A()
~B()~A()
~C()~A()
~C()~B()~A()
Code will not compile
Undefined behaviour

Explanation

Firstly, the type of ternary expression is converted to the base, in this case, B. Secondly, shared_ptr saves "deleter" for the correct deletion of an object and for this reason a virtual destructor is not required for it.

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