Question

Is the following code correct?


#include 
#include 

using namespace std;

int main() {
    vector v;
    v.resize(5);
    vector::iterator i = v.begin();
    *i = 5;
    v.resize(10);
    cout << "v.begin() = " << *i << endl;
}

Cosmo · Accepted Answer

After the second vector v resize operation the memory for its storage may be allocated starting from the new address, so there is no guarantee that the iterator that is stored in the i variable points to the correct memory area. Runtime error is possible / undefined behavior.

Cosmo · Accepted Answer

Runtime error is possible

Cosmo · Answer

Yes, the code will compile and run without errors

Cosmo · Answer

No, the code contains errors and will not compile

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