What is the result of the following code compilation and execution?

public class Clazz {
    private void process(String... s) {
        System.out.print("*");
    }
    private void process(String s) {
        System.out.print("1");
    }
    private void process(String s, String a) {
        System.out.print("2");
    }
    public static void main(String[] args) {
        Clazz c = new Clazz();
        c.process("asd");
        c.process("asd","asd");
        c.process("asd","asd","asd");
    }
}
Explanation
Methods with vararg-parameters are analysed in the last order by compiler - only if all other methods are not suitable. Process("asd") and process("asd", "asd") will be compiled without errors.
Java
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