Java quiz. What happens when the following class is compiled

What happens when the following class is compiled and executed?


public class VerySimpleClass {
  public static void main(String... args) {
     for (byte i = 6, j = 0 ; (j += i++) <= 10; i >>= 1, System.out.print(--j));
  }
}

Compilation error
Runtime error
Code will run and type 12358
None of the above

Explanation

Code will be compiled successfully since given form of the for loop is syntactically correct and does not contain errors. However, the program will fall into an infinite loop, because the value of the j is not growing and at the point of loop continuation condition check the variable j will always be equal to 1.