Question

What will be the result of the following code execution?


public class Test {
    public static void main(String args[]) {
        byte a = 1;
        byte b = ++a;
        byte c = -a;
        System.out.print(a);
        System.out.print(b);
        System.out.print(c);
    }
}

Cosmo · Accepted Answer

Compilation error will occur in the following line

byte c = -a;

since the result of the "-a" expression is of type int, despite the fact that the operand is byte. This is necessary to prevent possible loss of accuracy. For example, when a = -128 the received value exceeds a byte range.

It doesn't happen during an increment / decrement operations execution because, for example, for a = 127 the value of the ++a expression will be equal to -128.

Cosmo · Accepted Answer

Compilation error

Cosmo · Answer

22-2

Cosmo · Answer

12-2

Cosmo · Answer

11-1

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