Java quiz. What happens when you try to compile and run this

What happens when you try to compile and run this code:


public class Main {
    public static void main( String[] args ) {
        byte i = 2;
        byte j = 2;
        byte k = i * j;
        System.out.println(k);
    } 
}

The console will indicate "0"
The console will indicate "4"
There will be a compilation error
There will be a runtime error

Explanation

Before performing any arithmetic operations of the value of typebyte, short, char are automatically converted to the type int. Therefore, the result of the multiplication will also be of type int and then at compilation time the error of type mismatch will be found of variable byte k it's impossible to assign a value of type int.